1-(1/w)=(1/w^2)

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Solution for 1-(1/w)=(1/w^2) equation: 


D( w )

w^2 = 0

w = 0

w^2 = 0

w^2 = 0

1*w^2 = 0 // : 1

w^2 = 0

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

1-(1/w) = 1/(w^2) // - 1/(w^2)

1-(1/w)-(1/(w^2)) = 0

1-w^-1-w^-2 = 0

t_1 = w^-1

1-1*t_1^2-1*t_1^1 = 0

1-t_1^2-t_1 = 0

DELTA = (-1)^2-(-1*1*4)

DELTA = 5

DELTA > 0

t_1 = (5^(1/2)+1)/(-1*2) or t_1 = (1-5^(1/2))/(-1*2)

t_1 = (5^(1/2)+1)/(-2) or t_1 = (1-5^(1/2))/(-2)

t_1 = (5^(1/2)+1)/(-2)

w^-1-((5^(1/2)+1)/(-2)) = 0

1*w^-1 = (5^(1/2)+1)/(-2) // : 1

w^-1 = (5^(1/2)+1)/(-2)

-1 < 0

1/(w^1) = (5^(1/2)+1)/(-2) // * w^1

1 = ((5^(1/2)+1)/(-2))*w^1 // : (5^(1/2)+1)/(-2)

-2*(5^(1/2)+1)^-1 = w^1

w = -2*(5^(1/2)+1)^-1

t_1 = (1-5^(1/2))/(-2)

w^-1-((1-5^(1/2))/(-2)) = 0

1*w^-1 = (1-5^(1/2))/(-2) // : 1

w^-1 = (1-5^(1/2))/(-2)

-1 < 0

1/(w^1) = (1-5^(1/2))/(-2) // * w^1

1 = ((1-5^(1/2))/(-2))*w^1 // : (1-5^(1/2))/(-2)

-2*(1-5^(1/2))^-1 = w^1

w = -2*(1-5^(1/2))^-1

w in { -2*(5^(1/2)+1)^-1, -2*(1-5^(1/2))^-1 }

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